A right angled triangle ABC, where ∠B = 90°, is rotated about BC. If BC = 16 cm and AC = 20 cm, find the volume of the right circular cone traced out by the triangle.

2413 cm³

Given, h = 16 cm and l = 20 cm

$∴r=\sqrt{l^2-h^2}=\sqrt{20^2-16^2}cm=12cm$

∴ Volume = $\frac{1}{3}πr^2h$

$=\frac{1}{3}×\frac{22}{7}×12^2×16cm^2$

$=\frac{16896}{7}cm^3=2413cm^3$