The number of structurally isomeric alkyl halides possible for C5H11Cl is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 8
Structural isomers have the same molecular formula but a different arrangement of atoms: a different carbon chain, or the halogen on a different carbon.
To count the isomers of \( \ce{C5H11Cl} \), take each possible carbon skeleton of \( \ce{C5H12} \) and put the chlorine on each different kind of carbon in turn. Positions that are equivalent by symmetry give the same compound and are counted once.
\( \ce{C5H12} \) has three skeletons:
Pentane, \( \ce{CH3CH2CH2CH2CH3} \): three different positions (C1 = C5, C2 = C4, C3).
1-Chloropentane, \( \ce{CH3CH2CH2CH2CH2Cl} \)
2-Chloropentane, \( \ce{CH3CH2CH2CH(Cl)CH3} \)
3-Chloropentane, \( \ce{CH3CH2CH(Cl)CH2CH3} \)2-Methylbutane, \( \ce{(CH3)2CHCH2CH3} \): four different positions (C1 and the methyl on C2, which are equivalent; C2; C3; C4).
1-Chloro-2-methylbutane, \( \ce{ClCH2CH(CH3)CH2CH3} \)
2-Chloro-2-methylbutane, \( \ce{(CH3)2C(Cl)CH2CH3} \)
2-Chloro-3-methylbutane, \( \ce{(CH3)2CHCH(Cl)CH3} \)
1-Chloro-3-methylbutane, \( \ce{(CH3)2CHCH2CH2Cl} \)2,2-Dimethylpropane, \( \ce{C(CH3)4} \): all four methyl groups are equivalent, so only one position.
1-Chloro-2,2-dimethylpropane, \( \ce{(CH3)3CCH2Cl} \)
Total: 3 + 4 + 1 = 8 structural isomers. Stereoisomers are not counted here; 2-chloropentane, 1-chloro-2-methylbutane and 2-chloro-3-methylbutane each also exist as a pair of enantiomers.
NCERT (2026-27 edition):
Example 6.1 – “Draw the structures of all the eight structural isomers that have the molecular formula C5H11Br. Name each isomer according to IUPAC system and classify them as primary, secondary or tertiary bromide.
CH3CH2CH2CH2CH2Br 1-Bromopentane (1°)
CH3CH2CH2CH(Br)CH3 2-Bromopentane (2°)
CH3CH2CH(Br)CH2CH3 3-Bromopentane (2°)
(CH3)2CHCH2CH2Br 1-Bromo-3-methylbutane (1°)
(CH3)2CHCHBrCH3 2-Bromo-3-methylbutane (2°)
(CH3)2CBrCH2CH3 2-Bromo-2-methylbutane (3°)
CH3CH2CH(CH3)CH2Br 1-Bromo-2-methylbutane (1°)
(CH3)3CCH2Br 1-Bromo-2,2-dimethylpropane (1°)”