A solid cylinder of base radius 7 cm and height 11 cm is cut horizontally in two equal halves. Find the sum of the total surface of the two pieces (in $cm^2$). (if $\pi=\frac{22}{7}$)
Answer & explanation
Correct answer: option 4
Total surface area of cylinder = 2πr(r+h)
Whole cylinder is cut into two pieces vertically ,
So, New height = \(\frac{11}{2}\) = 5.5 & radius remains same.
total area of both the new surfaces = 2 × 2 × \(\frac{22}{7}\) × 7 (7+5.5)
= 88 × 12.5
= 1100
The correct answer is option (4) : 1100