Identify X in the following nuclear reaction:
${_6C}^{12}+{_1H}^1\rightarrow X$
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → ${_7N}^{13}$
$^{12}_{6}\text{C} + ^{1}_{1}\text{H} \rightarrow X$
$\text{Mass number: } 12 + 1 = 13$
$\text{Atomic number: } 6 + 1 = 7$
$X = \, ^{13}_{7}\text{N}$
The particle $X$ is $^{13}_{7}\text{N}$.