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Identify X in the following nuclear reaction: ${_6C}^{12}+{_1H}^1\rightarrow X$ |
${_7N}^{13}$ ${_5B}^{10}$ ${_6C}^{12}$ ${_7N}^{14}$ |
${_7N}^{13}$ |
The correct answer is Option (1) → ${_7N}^{13}$ $^{12}_{6}\text{C} + ^{1}_{1}\text{H} \rightarrow X$ $\text{Mass number: } 12 + 1 = 13$ $\text{Atomic number: } 6 + 1 = 7$ $X = \, ^{13}_{7}\text{N}$ The particle $X$ is $^{13}_{7}\text{N}$. |
