X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is Rs.110, then the money, which X has is:
Answer & explanation
Correct answer: option 4
Let Z's money = 2R, then
ATQ
Y : Z = 3R : 2R, and
X : Y = 6R : 3R
Here,
⇒ X + Y + Z = 3 × 110
⇒ 6R + 3R + 2R = 330
⇒ 11R = 330
⇒ 1R = 30
Therefore, X has = 6R = 6 × 30 = R.180