A parallel plate capacitor has two layers of dielectrics as shown in figure. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is
Answer & explanation
Correct answer: option 4
Capacitance (for k = 2)
$C_1=\frac{\varepsilon_0 kA}{d}$
$C_1$ = 2C Where C = $\frac{\varepsilon_0 A}{d}$
Capacitance (for k = 6)
$C_2 =\frac{6 \varepsilon_0 A}{2 d}$
$C_2$ = 3C
Therefore ratio of potential difference across the dielectric layer is = 3/2