Practicing Success
If $x^2-4 x+1=0$, then the value of $16\left(x^4-\frac{1}{x^4}\right)$ is |
127 255 $\frac{127}{16}$ $\frac{255}{16}$ |
255 |
If $x^2-4 x+1=0$ Then the value of $16\left(x^4-\frac{1}{x^4}\right)$ Divide by x on both sides of $x^2-4 x+4=0$ x + \(\frac{4}{x}\) = 4 Put the value of x = 2 (This value will satisfy the equation) $16\left(x^4-\frac{1}{x^4}\right)$ = $16\left(2^4-\frac{1}{2^4}\right)$ $16\left(x^4-\frac{1}{x^4}\right)$ = 16(\(\frac{256 - 1}{16}\)) $16\left(x^4-\frac{1}{x^4}\right)$ = 16 × \(\frac{255}{16}\) = 255 |