Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Algebra

Question:

If $\begin{bmatrix}1&3\\2&4\end{bmatrix}\begin{bmatrix}3&5\\-1&3\end{bmatrix}=\begin{bmatrix}m&14\\2&n\end{bmatrix}$, then $m+n$ is equal to

Options:

0

22

16

36

Correct Answer:

22

Explanation:

The correct answer is Option (2) → 22 **

Matrix multiplication:

$\begin{pmatrix}1 & 3 \\ 2 & 4\end{pmatrix} \begin{pmatrix}3 & 5 \\ -1 & 3\end{pmatrix}$

Thus:

$\begin{pmatrix}0 & 14 \\ 2 & 22\end{pmatrix} = \begin{pmatrix}m & 14 \\ 2 & n\end{pmatrix}$

So:

$m = 0$ and $n = 22$

$m + n = 22$

Answer: 22