If $\begin{bmatrix}1&3\\2&4\end{bmatrix}\begin{bmatrix}3&5\\-1&3\end{bmatrix}=\begin{bmatrix}m&14\\2&n\end{bmatrix}$, then $m+n$ is equal to |
0 22 16 36 |
22 |
The correct answer is Option (2) → 22 ** Matrix multiplication: $\begin{pmatrix}1 & 3 \\ 2 & 4\end{pmatrix} \begin{pmatrix}3 & 5 \\ -1 & 3\end{pmatrix}$ Thus: $\begin{pmatrix}0 & 14 \\ 2 & 22\end{pmatrix} = \begin{pmatrix}m & 14 \\ 2 & n\end{pmatrix}$ So: $m = 0$ and $n = 22$ $m + n = 22$ Answer: 22 |