Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If (7x - 10y) = 8 and xy = 5, then what is the value of $49x^2 +100y^2$?

Options:

764

632

623

746

Correct Answer:

764

Explanation:

(7x - 10y) = 8 and xy = 5

We know that,

 (a - b)2 = a2 + b2 - 2ab

= (7x - 10y)2 = 82

= 49x2 + 100y2 - 2 × 7x × 10y = 64

= 49x2 + 100y2 - 140xy = 64

= 49x2 + 100y2 = 64 + 140xy

= 49x2 + 100y2 = 64 + 140 × 5

= 49x2 + 100y2 = 764