Find all possible values of the given expression: $\sqrt{9-x^2}$

[1, 3] [2, 3] [0, 3] [0, 2]

[0, 3]

Least value of square root is 0, when $9 - x^2 = 0$ or x = ±3. Also, the greatest value of $9-x^2$ is 9, when x = 0. Hence, we have $0 ≤ 9 - x^2 ≤ 9⇒ \sqrt{9-x^2} ∈ [0,3]$