The value of magnetic field between plates of capacitor, at distance of 1m from centre where electric field varies by 1010 V/m/s will be:
Answer & explanation
Correct answer: option 4
$B=\frac{\mu_0 \varepsilon_0 r}{2} \frac{d E}{d t}=\frac{1}{2 \times 9 \times 10^{16}} \times 10^{10}=5.56 \times 10^{-8} T$