What is the least number which when divided by the number 6, 8, 9, 12, 14 leaves in each case a remainder 2 but when divided by 23 leaves no remainder?
Answer & explanation
Correct answer: option 1
1st method - Through option
Check option which is divisible 9 after substract 2 from the option.
Divisibly rule of 9 = Sum of digits are divisible by 9
So ans. option 1 - 506 satisfy, which is also divisible by 23.
2nd method
Required number = (LCM 6, 8, 9, 12, 14) + 2
= 504 + 2 = 506, which is also divisible by 23.