Practicing Success
The area to be covered for T.V. telecast is doubled, then the height of transmitting antena (T.V. tower) will have to be: |
doubled halved quardupled kept unchanged |
doubled |
The area of transmission surrounding the T.V. tower A = $\pi d^2=\pi(2 \mathrm{hRe})$ A $\propto$ h Hence the correct answer will be (A). |