If $tan^2x - 3 tanx + 2=0$ and (0° < x < 90°), then the value of x is :
Answer & explanation
Correct answer: option 3
tan²x - 3tanx + 2 - 0
tan²x - 2tanx - tanx + 2 - 0
tanx ( tanx - 2 ) - 1 ( tanx - 2 ) = 0
( tanx - 1 ). ( tanx - 2 ) = 0
Either ( tanx - 1 = 0 ) or ( tanx - 2 = 0 )
tanx - 2 = 0 is not possible
So, tanx - 1 = 0
tanx = 1
{ We know, tan45º = 1 }
So , x = 45º
45º