A train starts from a place at 10:00 a.m. and arrives at another place T at 2:30 p.m. on the same day. If the speed of the train is 40 m/sec, the what will be the distance covered by the train?

648 km

Total time taken b/w 10:00 am to 2:30 pm = 4 .5 hours

Speed = 40 m/sec

40 m/sec = 40 × \(\frac{18}{5}\) km/h = 144 km/h

Distance = Speed × Time

= 144 × 4.5 = 648 km

SO , Distance between A and B is 648km