Maximize \(Z=3x+5y,\) subject to \(x+4y\leq 24,3x+y\leq 21,x+y\leq 9,x\geq 0, y\geq 0\)
Answer & explanation
Correct answer: option 3
$Z(max)=Z(4,5)$
$=3×4+5×5$
$=37$
Maximize \(Z=3x+5y,\) subject to \(x+4y\leq 24,3x+y\leq 21,x+y\leq 9,x\geq 0, y\geq 0\)
Correct answer: option 3
$Z(max)=Z(4,5)$
$=3×4+5×5$
$=37$