Practicing Success
If 4sin θ = 3cos θ, then what is the value of cosecθ ? |
\(\frac{5}{4}\) \(\frac{5}{3}\) 1 0 |
\(\frac{5}{3}\) |
4sin θ = 3cos θ ⇒ \(\frac{sin θ}{cos θ}\) = \(\frac{3}{4}\) ⇒ tan θ = \(\frac{3 (P)}{4 (B)}\) using Pythagoras theorem , Hypotenuse = 5 cosecθ = \(\frac{H}{P}\)= \(\frac{5}{3}\) |