If x2 - 8x + 1= 0
and x > 1, then the value of
x3 + \(\frac{1}{x^3}\) will be:
Answer & explanation
Correct answer: option 2
If x2 - 8x + 1= 0
Divide by x on both sides,
x + \(\frac{1}{x}\) = 8
x3 + \(\frac{1}{x^3}\) = 83 - 3 × 8 = 488
Note - if x + \(\frac{1}{x}\) = a
then x3 + \(\frac{1}{x^3}\) = a3 - 3a