A 12 pF capacitor is connected to a 50 V battery. The electrostatic energy stored in the capacitor is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 1.5\times10^{-8}\,\mathrm{J} \)
Convert picofarad to farad first. The energy stored in a capacitor connected to a battery of voltage \( V \) is
\( \displaystyle U = \frac{1}{2}\,C V^{2} \)
\( C = 12\,\mathrm{pF} = 12\times10^{-12}\,\mathrm{F} \)
\( V = 50\,\mathrm{V} \)
\( \displaystyle U = \frac{1}{2} \times 12\times10^{-12} \times (50)^{2} = 6\times10^{-12} \times 2500 = 1.5\times10^{-8}\,\mathrm{J} \)
Note: This question is from NCERT (2026-27). NTA sets numerical questions from NCERT too, so do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
