Practicing Success
In an adiabatic process, R = \(\frac{2}{3}C_V\). The pressure of the gas will be proportional to : |
T5/3 T5/2 T5/4 T5/6 |
T5/2 |
\(R = \frac{2}{3}C_V\) We know : C_P - C_V = R \(\gamma - 1 = \frac{R}{C_v}\) \(R = C_V(\gamma - 1)\) Comparing : \(\gamma = \frac{5}{3}\) P\(1-\gamma\)T\(\gamma\) = constant = K \(P \propto T^{\frac{\gamma}{\gamma - 1}} \text{ ... [given : } \gamma = \frac{5}{3}]\) \(\frac{\gamma}{\gamma - 1} = \frac{5}{2}\) \(P \propto T^{5/2}\) |