What is the value of $\frac{sinA+B}{sinA cosB}$?

1 + cot A tan B 1 + tan A cot B 1 − sin A cos B 1− cot A tan B

1 + cot A tan B

\(\frac{sin (A+B)}{sinA.cosB}\) { formula used :- sin(A+B) = sinA.cosB + sinB.cosA } = \(\frac{ sinA.cosB + cosA.sinB }{sinA.cosB}\) = \(\frac{ sinA.cosB  }{sinA.cosB}\) +  \(\frac{ cosA.sinB }{sinA.cosB}\) = 1 + cotA .tanB