What is the value of $\frac{sinA+B}{sinA cosB}$?
Answer & explanation
Correct answer: option 1
\(\frac{sin (A+B)}{sinA.cosB}\)
{ formula used :- sin(A+B) = sinA.cosB + sinB.cosA }
= \(\frac{ sinA.cosB + cosA.sinB }{sinA.cosB}\)
= \(\frac{ sinA.cosB }{sinA.cosB}\) + \(\frac{ cosA.sinB }{sinA.cosB}\)
= 1 + cotA .tanB