Practicing Success
Practicing Success
CUET Preparation Today
If $ K + \frac{1}{K} - 2 = 0 $ and K > 0, then what is the value of $K^{17}+\frac{1}{k^{12}}$? |
2 1 0 12 |
2 |
If $ K + \frac{1}{K} - 2 = 0 $ put k = 1 $K^{17}+\frac{1}{k^{12}}$ = 1 + 1 = 2 |
