A parallel combination of resistances 10 Ω and 20 Ω is connected across a battery of 9.0 V. The current through the 20 Ω resistor is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0.45 A
Resistors in parallel each have the full battery voltage across them (battery taken as ideal), so each current follows from Ohm’s law separately.
\( \displaystyle I_{20} = \frac{V}{R} = \frac{9.0\,\mathrm{V}}{20\,\Omega} = 0.45\,\mathrm{A} \)