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Home Questions E6DEBFHD2V
Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Haloalkanes and Haloarenes

Question:

Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given.

Column I Column II
(a) CH4 + Cl2/hν → (i) CH3—Cl + POCl3 + H2O
(b) H2C=CH2 + HCl → (ii) CH3—I + NaBr
(c) CH3—OH + PCl5 → (iii) CH3—Cl + HCl
(d) CH3—Br + NaI/Acetone → (iv) CH3—CH2Cl

 

Options:

(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)

Correct Answer:

(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

Explanation:

Synthesis of Haloalkanes:

(a) From Alkanes: CH4 + Cl2/hν → CH3—Cl + HCl

(b) From Alkenes: H2C=CH2 + HCl → CH3—CH2Cl

(c) From Alcohols: CH3—OH + PCl5 → CH3—Cl + POCl3 + H2O

(d) From other halides: CH3—Br + NaI/Acetone → CH3—I + NaBr

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