Practicing Success
In nuclear reaction ${ }_2 H e^4+{ }_z X^A \rightarrow{ }_{z+2} Y^{A+3}+A, A$ denotes |
Electron Positron Proton Neutron |
Neutron |
The given equation is ${ }_2 H e^4+{ }_z X^A \rightarrow{ }_{z+2} Y^{A+3}+A, A$ Applying charge and mass conservation 4 + A = A + 3 + x ⇒ x = 1 ⇒ 2 + z = z + 2 + n ⇒ n = 0 Hence A is a neutron. |