In nuclear reaction ${ }_2 H e^4+{ }_z X^A \rightarrow{ }_{z+2} Y^{A+3}+A, A$ denotes
Answer & explanation
Correct answer: option 4
The given equation is ${ }_2 H e^4+{ }_z X^A \rightarrow{ }_{z+2} Y^{A+3}+A, A$
Applying charge and mass conservation
4 + A = A + 3 + x ⇒ x = 1 ⇒ 2 + z = z + 2 + n ⇒ n = 0
Hence A is a neutron.