Practicing Success
Triangle ABC is right angled at B and D is a point of BC such that BD = 5 cm, AD = 13 cm and AC = 37 cm. then find the length of DC in cm. |
25 30 5 35 |
30 |
Here, \(\Delta \)ABD is also a right angled triangle. So, \( { AB}^{2 } \) + \( { BD}^{2 } \) = \( { AD}^{2 } \) = \( { AB}^{2 } \) = 169 - 25 = AB = 12 we know, \( { AB}^{2 } \) + \( { BC}^{2 } \) = \( { AC}^{2 } \) = \( { BC}^{2 } \) = \( { AC}^{2 } \) - \( { AB}^{2 } \) = \( { BC}^{2 } \) = \( { 37}^{2 } \) - \( { 12}^{2 } \) = BC = 35 = BD + DC = 35 = DC = 30 Therefore, DC is 30 cm. |