Electrolytic conductivity of 0.30 M solution of KCl at 298 K is 3.72 x 10-2 S cm-1. What will be the molar conductance of the solution?
Answer & explanation
Correct answer: option 1
Molar Conductance, ΛM = \(\frac{1000 × Κ}{M}\)
ΛM = \(\frac{1000 × 3.72 × 10^{-2}}{0.30}\) = 124 S cm2 mol-1