The magnetic flux linked with a coil of N turns each having area of cross-section A, held in a magnetic field B with its plane parallel to the field, will be: |
Zero NBA BA -NBA |
Zero |
The correct answer is Option (1) → Zero The magnetic flux $(\phi_B)$ is - $\phi_B=N.B.A\cos θ$ As, Magnetic field B is parallel to the plane of area, $∵θ=0°$ $∴\phi_B=NBA\cos 0°$ $=NBA$ |