The magnetic flux linked with a coil of N turns each having area of cross-section A, held in a magnetic field B with its plane parallel to the field, will be:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Zero
The magnetic flux $(\phi_B)$ is -
$\phi_B=N.B.A\cos θ$
As, Magnetic field B is parallel to the plane of area,
$∵θ=0°$
$∴\phi_B=NBA\cos 0°$
$=NBA$