The magnetic flux linked to a coil changes from $10 \times 10^{-3} Wb$ to $6 \times 10^{-3} Wb$ in 0.01 s. The induced emf will be:

0.4 V

The correct answer is Option (2) → 0.4 V

$EMF=-\frac{d\phi_B}{dt}$

where,

$\frac{d\phi_B}{dt}$ = rate of change of magnetic flux.

$Δ\phi_B=-(6×10^{-3}-10×10^{-3})Wb$

$=-4×10^{-3}Wb$

$EMF=-\frac{d\phi_B}{dt}=\frac{4×10^{-3}}{0.01}=0.4V$