The last two digits of the product \( 4875\times 6788 \) are:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 00
The last two digits of a product depend only on the last two digits of the numbers:
\( 75\times 88=6600 \)
This ends in 00, so the required digits are 00.
Shortcut: The number 4875 is divisible by 25 and 6788 is divisible by 4, so the product is divisible by 100 and ends in 00.