A and B travel from X to Y at speeds of 40 km/hr and 60 km/hr respectively. If B takes \(\frac{1}{2}\) hour less than A, what is the distance between X and Y?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 60 km
Both cover the same distance, so the difference of their times is \(\frac{1}{2}\) hour.
Let the distance be \(d\) km: \(\displaystyle \frac{d}{40}-\frac{d}{60}=\frac{1}{2}\)
\(\displaystyle d\times\frac{3-2}{120}=\frac{1}{2}\), so \(\displaystyle \frac{d}{120}=\frac{1}{2}\)
\(d=60\) km
The distance between X and Y is 60 km.