The value of $\frac{sin30°cos60°+cos45°sin45°}{tan60°cot30°}$ is :
Answer & explanation
Correct answer: option 4
$\frac{sin30°cos60°+cos45°sin45°}{tan60°cot30°}$
= $\frac{1/2 × 1/2+1/√2× 1/√2}{√3×√3 }$
= $\frac{3/4}{3 }$
= \(\frac{1 }{4}\)
The value of $\frac{sin30°cos60°+cos45°sin45°}{tan60°cot30°}$ is :
Correct answer: option 4
$\frac{sin30°cos60°+cos45°sin45°}{tan60°cot30°}$
= $\frac{1/2 × 1/2+1/√2× 1/√2}{√3×√3 }$
= $\frac{3/4}{3 }$
= \(\frac{1 }{4}\)