CUET Preparation Today
A student goes to school at a speed of 5\(\frac{1}{2}\) km/h and comes back at a speed of 5 km/h. If he takes 5\(\frac{1}{4}\) hours for entire journey. Find the distance. |
22 km \(\frac{33}{2}\) \(\frac{55}{2}\) 33 km |
\(\frac{55}{2}\) |
D = \(\frac{2 × 11/2 × 5}{11/2 + 5}\) × \(\frac{21}{4}\) = \(\frac{11 × 5 × 2}{21}\) × \(\frac{21}{4}\) = \(\frac{55}{2}\) |
