CUET Preparation Today
The area (in Sq. units) of the region bounded by $y = -2,y=2,x=y^3$ and $x =0$ is equal to |
4 6 8 16 |
8 |
The correct answer is Option (3) → 8 $\text{Area}=\displaystyle\int_{-2}^{2}\left|\,0-y^{3}\,\right|\,dy=\int_{-2}^{2}|y^{3}|\,dy$ $=2\displaystyle\int_{0}^{2}y^{3}\,dy=2\left[\frac{y^{4}}{4}\right]_{0}^{2}=2\cdot\frac{16}{4}=8$ |
