If $x\sqrt{1+y}+y\sqrt{1+x}=0, $ then $\ - CUETMOCK

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Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

If $x\sqrt{1+y}+y\sqrt{1+x}=0, $ then $\frac{dy}{dx}=$

Options:

$\frac{1}{(1+x)^2}$

$\frac{-1}{(1+x)^2}$

$(1+x)^2$

$-(1+x)^2$

Correct Answer:

$\frac{-1}{(1+x)^2}$

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