CUET Preparation Today
Area of the region bounded by the curve $x^2=4 y$, x-axis and x = 3 is : |
$\frac{9}{2}$ sq. units $\frac{9}{4}$ sq. units $\frac{9}{5}$ sq. units $\frac{9}{8}$ sq. units |
$\frac{9}{4}$ sq. units |
$x^2=4 y$ x - axis, x = 3
so area = $\int\limits_0^3 y d x \Rightarrow \int\limits_0^3 \frac{x^2}{4} d x$ $\Rightarrow \left[\frac{x^3}{4 \times 3}\right]_0^3=\frac{3^3}{4 \times 3}=\frac{9}{4}$ sq. units |
