Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Logical and Analytical Reasoning

Topic

Calendar

Question:

In June 2009, 3rd Sunday was on which date?

Options:

20 June

19 June

22 June

21 June

Correct Answer:

21 June

Explanation:

\(\frac{Date + Month\;code + Century\;code + Century\;upper\;year + Upper\;year/4}{7}\)

⇒ \(\frac{1 + 4 + 6 + 9 + 9/4}{7}\) ⇒ \(\frac{1 + 4 + 6 + 9 + 2}{7}\)

⇒ \(\frac{22}{7}\) = Remainder 1

The day for Code 1 is Monday.

1st Sunday on 7th -

2nd Sunday on14th -

& 3rd Sunday on 21st -

Note:     

Code for      Mon – 1      Tues – 2      Wed – 3      Thurs – 4

                   Fri – 5         Sat ­­– 6        Sun – 0

Code for      Jan – 0        Apr – 6       July – 6       Oct – 0

                   Feb – 3       May – 1      Aug – 2       Nov – 3

                   Mar – 3       June – 4      Sep – 5       Dec – 5

Code for    1900 is 0

                  2000 is 6

                  2100 is 4

                  2200 is 2

                  2300 is 0

                  2400 is 6

                  2500 is 4 and Likewise.