If 2z = x + y, then the value of x/(x-z)+y/(y-z) is :

If 2z = x + y,

then the value of $\frac{x}{x-z}+\frac{y}{y-z}$

Put the value of z = 0, x = 1 and y = -1

$\frac{x}{x-z}+\frac{y}{y-z}$ = $\frac{1}{1-0}+\frac{-1}{-1-0}$

= 1 + 1 = 2