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If 2z = x + y, then the value of $\frac{x}{x-z}+\frac{y}{y-z}$ is : |
0 1 2 5 |
2 |
If 2z = x + y, then the value of $\frac{x}{x-z}+\frac{y}{y-z}$ Put the value of z = 0, x = 1 and y = -1 $\frac{x}{x-z}+\frac{y}{y-z}$ = $\frac{1}{1-0}+\frac{-1}{-1-0}$ = 1 + 1 = 2 |
