CUET Preparation Today
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$\text{Shift in position of central maxima along + y axis due to slit of width t is }\Delta y_1 = \frac{(2\mu -1)tD}{d}$ $\text{Shift in position of central maxima along - y axis due to slit of width 2t is }\Delta y_2 = -\frac{(\mu -1)2tD}{d}$ $\text{Net Shift is }\Delta y = y_1 - y_2 = \frac{tD}{d}$ |
