CUET Preparation Today
Find the integral \(\int\frac{( { x }^{ 2 } - 1)}{x-1}dx\) |
\[\frac{ { x }^{ 2 } }{2} - x +c\] \[\frac{ -{ x }^{ 2 } }{2} + x +c\] \[\frac{ { x }^{ 2 } }{2} + x +c\] \[\frac{ -{ x }^{ 2 } }{2} - x +c\] |
\[\frac{ { x }^{ 2 } }{2} + x +c\] |
\[\int x dx = \frac{ { x }^{ 2 } }{2}+c\] |
