A square shaped coil of 10 cm side, having 100 turns, is placed perpendicular to a magnetic field which is increasing at the rate of 1.0 T/s. The induced emf in the coil would be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1.0 V
By Faraday's law, the magnitude of the induced emf equals the rate of change of the magnetic flux linkage. The plane of the coil is perpendicular to the field, so the flux through each turn is \( BA \).
\( \displaystyle \varepsilon = N A \frac{dB}{dt} \)
\( N = 100 \)
\( A = (10\,\mathrm{cm})^{2} = (0.1\,\mathrm{m})^{2} = 0.01\,\mathrm{m^{2}} \)
\( dB/dt = 1.0\,\mathrm{T\,s^{-1}} \)
\( \displaystyle \varepsilon = 100 \times 0.01\,\mathrm{m^{2}} \times 1.0\,\mathrm{T\,s^{-1}} = 1.0\,\mathrm{V} \)