A dealer buys an old cooler listed at ₹650 and gets successive discounts of 20% and 10%. He spends ₹38 on its repairs and sells it at a profit of 20%. Find the selling price of the cooler.

₹607.2

Given:

Marked price = Rs. 650

Discounts = 20% and 10% (Successive discount = 28%)

The cost of repairs = Rs. 38

Selling profit = 20%

ATQ,

CP = 650 ×  \(\frac{100 - 28}{100}\) + 38 = 506

Selling price at 20% profit = 120% of 506 = â‚¹607.2