The value of b, for which the function $f(x) =\left\{\begin{matrix} 5x-4 & 0< x ≤1\\4x^2 +3bx & 1< x < 2\end{matrix}\right.$ is continuous at every point of its domain is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → -1
$f(x) =\left\{\begin{matrix} 5x-4 & 0< x ≤1\\4x^2 +3bx & 1< x < 2\end{matrix}\right.$
$f(1)=5(1)-4=1$
$\lim\limits_{x→1^+}f(1)=4(1)^3+3b(1)$
so $4+3b=1$
$b=-1$ for continuity to exist