Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

A planet of mass 3 × 1029 gm moves around a star with a constant speed of 2 × 106 ms–1 in a circle or radius 1.5 × 1014 cm. The gravitational force exerted on the planet by the star is

Options:

6.67 × 1022 dyne

8 × 1027 dyne

8 × 1026 N

6.67 × 1019 N

Correct Answer:

8 × 1026 N

Explanation:

Gravitational force supplies centripetal force

∴  F = $\frac{\mathrm{mv}^2}{\mathrm{r}}=\frac{3 \times 10^{29} \times\left(2 \times 10^8\right)^2}{1.5 \times 10^{14}}$ dyne

= 8 × 1031 dyne = 8 × 1026 N