Match List-I with List-II
Choose the correct answer from the options given below : | ||||||||||||||||||||
(A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) |
(A)-(II), (B)-(I), (C)-(IV), (D)-(III) |
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A) $∫\frac{dx}{a^2-x^2}⇒\frac{1}{2a}\log\left|\frac{a+x}{a-x}\right|+C$ (II) (B) $∫\frac{dx}{x^2-a^2}⇒\frac{1}{2a}\log\left|\frac{x-a}{x+a}\right|+C$ (I) (C) $∫\frac{dx}{x^2+a^2}⇒\frac{1}{a}\tan^{-1}\frac{x}{a}+C$ (IV) (D) $∫\frac{dx}{\sqrt{a^2-x^2}}⇒\sin^{-1}\frac{x}{a}+C$ (III) |