If N + 1/N = √3, then find the value of N^6 +1/(N^6)+11.

If $N + \frac{1}{N} = \sqrt{3}$

Then find the value of $N^6 +\frac{1}{N^6}+11$ ?

We know a direct result =

If $N + \frac{1}{N} = \sqrt{3}$

Then N⁶ = -1 ( Always)

 $N^6 +\frac{1}{N^6}+11$ = -1 -1 + 11 = 9