$y=e^{\sin 2 x}$, then $\frac{d y}{d x}$ is

x cos 2x 2y cos 2x xy cos 2x none of these

2y cos 2x

$y=e^{\sin 2 x} \Rightarrow \frac{d y}{d x}=e^{\sin 2 x} \cos 2 x . 2=2 e^{\sin 2 x} . \cos 2 x$ Hence (2) is correct answer.