Practicing Success
Practicing Success
CUET Preparation Today
An EM wave travelling in vacuum is described by $\vec{E}=\vec{E}_0 \sin (k x-\omega t) \hat{j}$ and $\vec{B}=\vec{B}_0 \sin (k x-\omega t) \hat{k}$ Which of the following relation is true? |
$E_0 k=B_0 \omega$ $E_0 \omega=B o K$ $E_0 B_0=k \omega$ $\frac{B_o}{E_o}=\sqrt{\omega / k}$ |
$E_0 k=B_0 \omega$ |
The correct answer is Option (1) → $E_0 k=B_0 \omega$ |
