The Table presents the amount of milk (in litres) sold by two milkmen in eight days.

The total amount of milk (in litres) sold by milkman in all 8 days is what percent(correct to one decimal place) more than the total amount of milk sold by milkman 1 in first six days?

55.6

Milk sold by milkman 2 in all 8 days = 31 + 32 + 43 + 41 + 49 + 59 + 62 + 69

= 386

Milk sold by milkman 1 in all 8 days = 28 + 34 + 38 + 37 + 53 + 58

= 248

required percentage = \(\frac{386 - 248 }{248}\) × 100

= \(\frac{138 }{248}\) × 100

= 55.6%