The Table presents the amount of milk (in litres) sold by two milkmen in eight days.
|
Days |
Milkman 1 |
Milkman 2 |
|
1 |
28 |
31 |
|
2 |
34 |
32 |
|
3 |
38 |
43 |
|
4 |
37 |
41 |
|
5 |
53 |
49 |
|
6 |
58 |
59 |
|
7 |
63 |
62 |
|
8 |
67 |
69 |
The total amount of milk (in litres) sold by milkman in all 8 days is what percent(correct to one decimal place) more than the total amount of milk sold by milkman 1 in first six days?
Answer & explanation
Correct answer: option 1
Milk sold by milkman 2 in all 8 days = 31 + 32 + 43 + 41 + 49 + 59 + 62 + 69
= 386
Milk sold by milkman 1 in all 8 days = 28 + 34 + 38 + 37 + 53 + 58
= 248
required percentage = \(\frac{386 - 248 }{248}\) × 100
= \(\frac{138 }{248}\) × 100
= 55.6%