Let \(f(x)=\frac{1}{4x^2+2x+1}\). then its maximum value is
Answer & explanation
Correct answer: option 3
Find minimum value of \(4x^2+2x+1=4(x+\frac{1}{4})^2+\frac{3}{4}\)
Let \(f(x)=\frac{1}{4x^2+2x+1}\). then its maximum value is
Correct answer: option 3
Find minimum value of \(4x^2+2x+1=4(x+\frac{1}{4})^2+\frac{3}{4}\)